php获取url内容 php请求url并接收返回值?
php请求url并接收返回值?$ch=curluuinit()curlusetopt($ch,CURLOPTuurl,$uri)curlusetopt($ch,CURLOPTuupost,1)//设置
php请求url并接收返回值?
$ch=curluuinit()
curlusetopt($ch,CURLOPTuurl,$uri)
curlusetopt($ch,CURLOPTuupost,1)//设置为Post
curlusetopt($ch,CURLOPTuheader,0)
curlusetopt($ch,CURLOPTureturntransfer,1)
curlsetopt($ch,CURLOPTupostfields,$data)//data是post请求的参数
$return=curlExec($CH)//$return是收到的返回值
curlclose($CH)